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Ksenya-84 [330]
3 years ago
5

Suppose AABC has coordinates A(2,3), B(5, 1), C(4.4), line m is the line with equation y = -5, and AABC is mapped to AA'B'C' by

applying the glide
reflection T(-2, 1) Rm Select all the statements that are true about AA'B'C'.



A All the vertices of LA'B'C' are in Quadrant II
B. All the vertices of AA'B'C' are in Quadrant IV.
C. The x-coordinates of A', B, and C are all negative,
D. The y-coordinates of A, B, and C are all positive,
E The y-coordinates of A' B', and C are all negative,

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0
I think it’s a I hope I’m not wrong
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Answer:

1. 392

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1. 7×8 + 3×8×14 = 56 + 336 = 392

2. 675 ÷ (6 + 3) = 675 ÷ 9 = 75

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Pls help me in this i really need help :( :)
Andrews [41]

Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step:</u>

<u>First off, let's write the line in point-slope form:</u>

  \rm \hookrightarrow (y-y_0)=m(x-x_0)

  • (x₀, y₀) any random point on the line
  • 'm' is the value of the slope

<u>Let's calculate the slope:</u>

 \rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}

  • (x₁, y₁): any random point on the line                                     ⇒   (-2, -6)
  • (x₂,y₂): any random point on the line that is not (x₁, y₁)         ⇒   (2, -3)

                 \rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}

<u>Now that we found the slope, let's put it into the point-slope form</u>

  ⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

     (y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)

<u>The equation, however, could also be put into 'slope-intercept form'</u>

     ⇒ gotten by isolating the 'y' variable to the left

          y = \frac{3}{4}x-\frac{9}{2}  

<u>Answer:</u>y = \frac{3}{4}x-\frac{9}{2} or y+3=\frac{3}{4} (x-2)

   *<em>Either equations work, put the one that you are the most familiar with</em>

Hope that helps!

#LearnwithBrainly

5 0
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Help pretty please .w.
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Answer:

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