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Lapatulllka [165]
3 years ago
9

Three more than twice a number is 15 in algebraic equation

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0
3 + 2n = 15

hope this helps
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Three brothers have ages that are consecutive even integers. the product of the first and third boys' ages is 20 more than wice
vladimir1956 [14]
Let the first brother = x 
second brother = x + 2
third brother = x + 4

<span>The product of the first and third boys' ages is 20 more than twice the second boy's age:

x(x+4) = 2(x+2) + 20
x</span>² + 4x = 2x + 4 + 20
x² + 4x - 2x - 24 = 0
x² + 2x - 24 = 0
(x - 4)(x + 6) = 0
x = 4 or -6 (rejected, age cannot be negative)

First brother = 4
Second brother = 4 + 2 = 6
Third brother = 4 + 4 = 8

The three boys are 4, 6, and 8 years old. 

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Answer:

I think it might become a 76.5%

Step-by-step explanation:

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I really hope this helps!!

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32.043 in expanded form?
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