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ivolga24 [154]
3 years ago
9

if one m&m is randomly selected from a dish containing 7 green, 4 red, 5 blue and 8 yellow m&ms, find the probability th

at a red is selected
Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Answer:

1/6 = 16.67%

Step-by-step explanation:

There are a total of 24 m&ms. The probability of picking an m&m that has a quantity of 4 is 4/24 = 1/6 = 16.67%

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Will Mark brainliest if correct. Will report if not correct.
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Answer:

Looks like the scale factor is 1/3.

Step-by-step explanation:

<em>(In this dilation, the green image is polygon ABCDE, and the red image is polygon A'B'C'D'E'. The red image is the resulting image after said dilation.)</em>

A scale factor greater than one enlarges an image, and a scale factor between zero and one shrinks an image, so that rules out options 2 (SF = -3) and 3 (SF = 3).

A negative scale factor would end up in an image opposite the center of enlargement, so that eliminates option 4 (SF = -1/3).

So that means that the scale factor is option 1 (SF = 1/3)!

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a bag of apples weighs 7 7/8 pounds. by weight 1/18 of the apples are rotten. what is the weight of the good apples?
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The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviatio
Scrat [10]

This question not incomplete

Complete Question

The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%

Answer:

0.125

Step-by-step explanation:

Assuming for 95%

z score for 95th percentile = 1.645

We find the Probability using z table.

P(z = 1.645) = P( x ≤ 7000)

= P(x<Z) = 0.95

After 7000 hours = P > 7000

= 1 - P(x < 7000)

= 1 - 0.95

= 0.05

If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:

(P > 7000)³

(0.05)³ = 0.125

7 0
3 years ago
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