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3 years ago

9

if one m&m is randomly selected from a dish containing 7 green, 4 red, 5 blue and 8 yellow m&ms, find the probability th

at a red is selected

1 answer:

Bad White [126]3 years ago

6 0

Answer:

1/6 = 16.67%

Step-by-step explanation:

There are a total of 24 m&ms. The probability of picking an m&m that has a quantity of 4 is 4/24 = 1/6 = 16.67%

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3 years ago

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Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

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