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jeka57 [31]
3 years ago
13

At the beginning of the school year, Jamie had $500 in her savings account. She wants to have at least $200 left in the account

at the end of the school year. Each week, she withdraws $30 for spending money. To determine how many weeks she can spend $30, Jamie wrote and solved this inequality.
500 − 30x ≥ 200
−500 −500
−30x ≥ −300
x ≥ 10
Review Jamie’s work. What was her error?
Mathematics
2 answers:
Black_prince [1.1K]3 years ago
8 0

Answer:

Jamie should have reversed the inequality when using the division property of inequality.

Step-by-step explanation:

UNO [17]3 years ago
7 0

Her error was that she misplaced the numbers

-30x ≥ -300

its supose

to be -30x ≥ 200

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solniwko [45]

Answer:

Step-by-step explanation:

The admission to the fair is $5 and the cost per ride is 50 cents.

Let the number of rides that he can go on be x

If one ride costs 50 cents, x rides will cost 50×x = 50x cents. Converting 50 cents to dollar, it becomes 50/100 = $0.5.

So x rides will cost $0.5x

If his parents gave him $20, he will pay $5 to be admitted into the fair. He would be left with 20- 5 = $15

The equation to find how many rides he can go on will be

0.5x = 15

Since one ride costs $0.5

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x = 15/0.5 = 30

He can go on 30 rides

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Katyanochek1 [597]

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If you are reducing it as a fraction, it is not possible because there is no other number to reduce it, so it will be in it's simplest form already.

8 0
2 years ago
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In circle F with m∠EFG=54m∠EFG=54 and EF=19
elena-14-01-66 [18.8K]

Answer:

17.907082 unit

Step-by-step explanation:

According to the Question,

Given, A circle with centre F, ∠EFG=54 and EF=19 .

length of arc EG = Radius(EF) × ∠EFG(in Radian)

  • We Know, 1 degree = 0.0174533 Radian
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(For Diagram please find in attachment)

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3 years ago
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olganol [36]

Answer:

\large\boxed{f(1-x)=x^2-4x+5}

Step-by-step explanation:

f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2

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