All categories

3 years ago

(10n-5)÷(5)=2n-1 the left of the parentheses has to equal the right

Mathematics

1 answer:

daser333 [38]3 years ago

8 0

(10n-5)/(5)= 2n-1
just divide
10/5 = 2 and -5/5 =-1
and you get the answer
2n-1= 2n-1

You might be interested in

Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0

drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

Step-by-step explanation:

The given is,

$2x+2y+z=- 2$ .......................................(1)

$-x-2y+2z=-5$ ......................................(2)

$2x+4y+z=0$ .........................................(3)

Step:1

Equation (2) is multiplied by -1 ( Eqn(2) × -1 )

$x+2y-2z=5$ .............................(4)

Subtract the equation (1) and (4)

$2x+2y+z=- 2$

$x+2y-2z=5$

( - )

$(2x-x)+(2y-2y)+(z+2z)=(-2-5)$

$x+3z=-7$ ......................(5)

Step:2

Equation (2) is multiplied by -2 ( Eqn(2) × -2)

$2x+4y-4z=10$ ........................(6)

Subtract equation (6) and (3),

$2x+4y-4z=10$

$2x+4y+z=0$

( - )

$(2x-2x)+(4y-4y)+(-4z-z)= (10-0)$

$-5z=10$

$z = - \frac{10}{5}$

z = -2

From the equation (5),

$x+3z=-7$

$x+(3)(-2)=-7$

$x = -7+6$

x = -1

From equation (1),

$2x+2y+z=- 2$

Substitute x and z values,

$(2)(-1)+2y+(-2)=-2$

$2y - 4=2$

$2y=4-2$

$2y=2$

$y=\frac{2}{2}$

y = 1

Step:3

Check for solution,

$-x-2y+2z=-5$

Substitute x,y and z values,

$-(-1)-(2)(1)+(2)(-2)=-5$

$1-2-4=-5$

-5 = -5

Result:

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

8 0

3 years ago

I NEED HELP PLEASEEE

Gwar [14]

Answer:

b = $\sqrt{333}$

Step-by-step explanation:

1. We can use the Pythagorean Theorem to find the missing side, b.

$14^2 + b^2 = 23^2$

2. (Solving)

Step 1: Simplify both sides of the equation.

$(14*14)+b^2 =(23*23)$
$196 + b^2 = 529$

Step 2: Subtract 196 from both sides.

$196 + b^2 - 196 = 529 - 196$
$b^2 = 333$

Step 3: Take square root of both sides.

$\sqrt{b^2} = \sqrt{333}$
$b = \sqrt{333}$

Step 4: Check if solution is correct.

$14^2 + \sqrt{333^2} = 23^2$
$(14*14)+(\sqrt{333} *\sqrt{333})=23*23$
$196 + 333 = 529$
$529 = 529$

Therefore, b = $\sqrt{333}$ .

6 0

2 years ago

Read 2 more answers

Determine whether the systems have one solution, no solution, or infinitely many solutions. 3x-2y=3; 6x-4y=1

Alik [6]

The equation has no solution.

<h3>How to solve the equation?</h3>

The equation given is illustrated as:

3x-2y=3 .... i

6x-4y=1 ..... ii

Multiply equation i by 6

Multiply equation ii by 3

18x - 12y = 18

18x - 12y = 3

Subtract the equations.

This will give 0. Therefore, the equations gas no solution.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

3 0

2 years ago

Solve for v.<br>2= 11 – 3v

Nastasia [14]

Answer:

v= 3

Step-by-step explanation:

2-11= -9

-3v/ -9

= 3

8 0

3 years ago

A ferris Wheel has a radius of 65 feet. What is the circumference of the wheel?

MAXImum [283]

Answer:

63 in.3 that's what I got so I hope it's right

7 0

2 years ago