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Wewaii [24]
3 years ago
7

(10n-5)÷(5)=2n-1 the left of the parentheses has to equal the right

Mathematics
1 answer:
daser333 [38]3 years ago
8 0
(10n-5)/(5)= 2n-1
just divide
10/5 = 2 and -5/5 =-1
and you get the answer
2n-1= 2n-1
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Given rectangle QUAD, If DU = 5x - 4 and QP = 2x + 7, then find the length of DU.
ira [324]

Answer:

DU = 86

Step-by-step explanation:

Properties of a rectangle,

- Opposite sides are equal in measure.

- Diagonals of a rectangle are equal.

- Diagonals bisect each other.

In the given rectangle QUAD,

Diagonals AQ and DU bisect each other at P.

AQ = DU

2(QP) = DU [Since, AQ = 2(PQ)]

2(2x + 7) = 5x - 4

4x + 14 = 5x - 4

5x - 4x = 14 + 4

x = 18

Since, DU = 5x - 4

DU = 5(18) - 4

     = 90 - 4

     = 86

Therefore, measure of DU = 86 units

3 0
2 years ago
How do i do this some one please explain
Talja [164]

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We know that 1 mile = $3.50

And that the tow company towed the car 12 miles.

So we would have to multiply 12 by $3.50

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12 x $3.50 = $42.00

So your answer is D. $42.00

4 0
3 years ago
1. The point (–1, 13) is on the terminal side of an angle in standard position. Use this
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3 years ago
Can I get some help please? <br><br><br> Thanks!
quester [9]
An ellipse (oval shape) is expressed by the following equation:

\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1 where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).

We can find the foci by using a^2 - b^2 = c^2

36 - 11 = c^2

c =  \sqrt{25}  = 5

Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.

So the foci are (-5, 0) and (5, 0)

Hope this helps :)

3 0
3 years ago
Please choose the correct answers !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!
vladimir2022 [97]
The answer is A, C ,B
5 0
3 years ago
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