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vaieri [72.5K]
3 years ago
13

You need to determine the mass of a sample of an element for a science project. The element is in the shape of a rectangular pri

sm with a length of 0.5 centimeters, a width of 0.2 centimeters, and a height of 0.3 centimeters. The density of the element is 2.7 grams per cubic centimeter. Find the mass of the element. (round to the nearest hundredth)
Mathematics
1 answer:
zheka24 [161]3 years ago
4 0

Answer:

The mass of the prism is approximately 0.08 grams.

Step-by-step explanation:

The first step to determine the mass, is to calculate the volume of the prism, this can be done using the formula below:

volume = height*length*width

volume = 0.3*0.5*0.2 = 0.03 cm³

Now we need to multiply the volume by the density of the material in order to find it's mass.

mass = volume*density

mass = 0.03*2.7 = 0.081 grams

The mass of the prism is approximately 0.08 grams.

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-4(2x + 4) > 8x + 64
romanna [79]

Hello there I hope you are having a great day :)

Your Question, -4(2x + 4) > 8x + 64 Solve for X

1) Expand -8x-16>8x+64

2) Add 16 to both sides -8x-16+16>8x+64+16

3) Simplify -8x>8x+80

4) Subtract 8x from both sides -8x-8x>8x+80-8x

5) Simplify -16x>80

6) Multiply both sides -1 (Reverse the inequality) (-16x) (-1) >80 (-1)

7) Simplify 16x<-80

8) divide both sides by 16   16x/16 <  -80/16

9) Simplify x < -5  

This should be your answer x < -5

Hopefully that helps you :)

5 0
2 years ago
Read 2 more answers
A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at
icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder,  H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from  Pythagoras theorem,

B² + P² = H²    .

or

B² + P² = 6²          ..............(1)      [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

or

P² = 36 - 1.69

or

P² = 34.31

or

P = 5.857

Now,

differentiating (1)

2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

or

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × (\frac{dP}{dt}) = 0

or

1.14 + 11.38 × (\frac{dP}{dt}) = 0

or

11.38 × (\frac{dP}{dt}) = - 1.14

or

(\frac{dP}{dt}) = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

5 0
3 years ago
Solve for x: 2 over 3 equals 8 over quantity x plus 6
SashulF [63]

Answer:

x = 40/3

Step-by-step explanation:

2/3 = (8/x) + 6

-6                -6

2/3 - 6 = -16/3

-16/3 = 8/x

*x          *x

(-16/3)x = 8

+16/3     +16/3

x = 40/3

7 0
3 years ago
Read 2 more answers
What is the anwser to this equation? 36=15+7x
deff fn [24]

Answer:

x = 3

Step-by-step explanation:

  1. Subtract 15 from each side, so it now looks like this: 21 = 7x
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I hope this helps!

7 0
3 years ago
Read 2 more answers
Perform the modular arithmetic. (7 · 15) (mod 4)
Reika [66]

We could do it by first writing

7\cdot15=(4+3)\cdot(4+11)=4^2+14\cdot4+33

so that

7\cdot15\equiv4^2+14\cdot4+33\equiv33\pmod4

and since 33=32+1=8\cdot4+1, we have

7\cdot15\equiv33\equiv1\pmod4

# # #

Alternatively, we can just compute the product and take it mod 4:

7\cdot15=105=104+1=26\cdot4+1

and so we get the same result of 1.

4 0
3 years ago
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