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swat32
3 years ago
5

Please help answer this I need help badly

Mathematics
2 answers:
VLD [36.1K]3 years ago
5 0
The radius is 2 (C^2-B^2==A^2)
Viefleur [7K]3 years ago
4 0
It should be 2 ..............
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in a town election, 5985 people voted. this is 63% of the town's population who are registered to vote. How many people are regi
dangina [55]

Answer:

  9500

Step-by-step explanation:

If r represents the number of registered voters, we are given that ...

  5985 = 0.63·r

  r = 5985/0.63 = 9500

9500 people are registered to vote.

5 0
3 years ago
Sydney asked her friends to write down the number of hours they practice their instruments each week. The data is shown.
AnnyKZ [126]
The median in this data set is C. 5
8 0
3 years ago
In one city, taxi company A charges $5 plus $0.35/km travelled. Taxi company B charges $3.50 plus $0.50/km.
lions [1.4K]

Answer:

If you are asking for the equations, Company A would be 0.35x + 5 and Company B would be 0.50x + 3.50. :)

Step-by-step explanation:

3 0
3 years ago
2.0Plss solve for x...........................
Paul [167]

Answer:

x = - 7

Step-by-step explanation:

( x + 139 ) and 132 are vertically opposite angles.

Vertically opposite angles are equal,

x + 139 = 132

x = 132 - 139

x = - 7

7 0
3 years ago
The population of a rabbit colony triples every 3 days. The population starts at 10 rabbits. Write an exponential function that
qaws [65]

Answer:

Step-by-step explanation:

The population at various days is as follows since population triples every 3 days

<u>Day</u>     <u>Population</u>

0          10

3          30

6          90

9          270

....         ......

This can be modeled by the general equation

n_{t} = n_{0}(r)^{t/k}

where

n_{t} is the population after t days

n_{0} is the population at start (10)

r is the rate at which population changes ie 3

t is the number days from start

k is the number of days at which the population triples(here k =3 days)

We can check this by plugging in values for each of the variables

At day 0, population = 10(3)⁰ = 10. 1 = 10

Similarly populations for days 3, 6, 9 are:

\\\\10.3^{3/3} = 10. 3^1 = 10.3 = 30\\10.3^{6/3} = 10. 3^2 = 10.9 = 90\\\\10.3^{9/3} = 10. 3^3 = 10.27 = 270

8 0
1 year ago
Read 2 more answers
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