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tiny-mole [99]
3 years ago
9

Yukiko has 10,000 cubic centimeters of sand in a bag.She turns the pyramid shown upside down and pours the sand into it .Wjat fr

action of the pyramid can she fill with her bag of sand? when you have 60 cm deep and 40 cm wide by 30 cm length
Mathematics
1 answer:
stepan [7]3 years ago
7 0
She can fill 5/12 of the pyramid.

The volume of a pyramid is given by the formula 
V = 1/3lwh.  Using our information, we have:

V = 1/3(40)(30)(60) = 24000 cm³

She has 10,000 cm³ of sand; 10000/24000 = 5/12.
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A scientist running an experiment starts with 100 bacteria cells. These bacteria double their population every 15 hours. Find ho
IRISSAK [1]
<h2>Hello!</h2>

The answer is: 23.77 hours

<h2>Why?</h2>

Total(t)=Start*2^\frac{t}{15}

Where:

Total(t) is equal to the amount for a determined time (in hours)

<em>Start</em> is the original amount

<em>t </em>is the time in hours.

For example, it's known from the statement that the bacteria double their population every 15 hours, so it can be written like this:

Total(15)=100*2^\frac{15}{15}=100*2^{1}=100*2=200

To calculate how long it takes for the bacteria cells to increase to 300, we should do the following calculation:

300=100*2^{\frac{t}{15} } } \\\frac{300}{100}=2^{\frac{t}{15} } }\\log(3)=log(2^{\frac{t}{15} })\\\\\\log(3)=\frac{t}{15}*log2\\t=\frac{log(3)}{log(2)} *15=23.77

So, to know if we are right, let's replace 23.77 h in the equation:

Total(t)=100*2^\frac{23.77}{15}=299.94

and 299.94≅300

Have a nice day!

8 0
3 years ago
Read 2 more answers
Find the value of x.
natulia [17]

Answer: sorry its not big enough to see sorry

Step-by-step explanation:

6 0
3 years ago
Please help me i don't understand what my answer should be . i'll give brianliest jus please help
AnnyKZ [126]

Answer:

Step-by-step explanation:

1. ABE bc the both have a right angle. plus when added together, they make a square which means they are the same.

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6 0
3 years ago
Read 2 more answers
A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.
gayaneshka [121]

9514 1404 393

Answer:

  4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

  s = 16t²

So, the time required to fall distance s is ...

  t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

  s = 1100t

  t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

  (1/4)√s + s/1100 = 20

  275√s = 22000 -s . . . . . multiply by 1100 and subtract s

  75625s = s^2 -44000s +484,000,000 . . . square both sides

  s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

  s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

<em>Additional comment</em>

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0
3 years ago
Find a cubic function with the given zeros.
Fed [463]

Answer:

The correct option is D) f(x) = x^3 + 2x^2 - 2x - 4 .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x + 4 .

f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 + 2x - 4 .

f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 - 2x^2 - 2x - 4 .

f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0

Now check for other roots as well.

Substitute x=√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0

Substitute x=-√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0

Therefore, the option is correct.

8 0
3 years ago
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