This is how you solve this problem:
.10d + .05n = 5.25
(plug in the number of dimes we have)
(21 x .1) + .05n = 5.25
(multiply number of dimes x value of the dime)
2.10 + .05n = 5.25
(subtract 2.10 from both sides)
.05n = 3.15
(divide both sides by .05 to get the number of nickels)
n = 63 nickels
Hope this helps!
Answer:
75
Step-by-step explanation:
Giving Q was not necessary because you aren't doing P(Q) or anything like that....
Anyways,

Since you're doing p(8), you would replace the x's with 8s.

So your final answer would be 75.
Answer:
Whats the question so that I can help?
Step-by-step explanation:
<h2>
Answer:</h2>
Option: D is the correct answer.
D. (2,54)
<h2>
Step-by-step explanation:</h2>
We know that an outlier of a data set is the value that stands out of the rest of the data point i.e. either it is a too high value or a too low value as compared to other data points.
Here we are given a set of data points as:
(2,54)
(4,7)
(6, 9)
(8,12)
(10,15)
Hence, we see that the output values i.e. 7 in (4,7) ; 9 in (6,9) ; 12 in (8,12) and 15 in (10,15) are closely related.
Hence, the data point that is an outlier is:
(2,54)
(As 54 is a much high value as compared to other)
Do you have another picture?