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2 years ago

What is the probability of Sunday following Saturday this week?

Mathematics

2 answers:

frozen [14]2 years ago

6 0

Answer:

certain

Step-by-step explanation:

the probability called certain means that is will occur or it's probability is 1

ser-zykov [4K]2 years ago

6 0

Answer:

Certain or 1/1 - 2/2 - 3/3 - 4/4 ect.

Step-by-step explanation:

Unless the world ends on Saturday (which is looking more and more certain as the year goes on) Sunday will follow after it the next day.

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Will Mark Brainliest!!! Please Help

tresset_1 [31]

(1) Outcomes

(2) Permutation

(3) Tree Diagram

(4) Counting Principle

(5) Combination

(6) Factorial

(7) Addition Principle of Counting

(8) Multiplication Principle of Counting

Hope this helps

-Amelia The Unknown

3 0

3 years ago

A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia

iogann1982 [59]

$\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\$

$\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}$

what's the population in 2004? well, from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004

3 0

2 years ago

Simplify. 5 - 2(x - 3)

V125BC [204]

To solve this, we simply need to remember our rules about order of operations. They tell us that first, we should distribute the 2 with the rest of the parentheses.

5-2(x-3)
5-2x+6

Next, we should combine our like-terms.

5-2x+6
11-2x

Seeing as we do not know the value of the variable, the simplest form of the expression is 11-2x.

3 0

2 years ago

2.Solve the following quadratic equations i. 9x^2 - 1/16 ii. 2h^2 - 3h - 27

Juli2301 [7.4K]

$i)~9x^2-\dfrac{1}{16}=0\iff9x^2=\dfrac{1}{16}\iff x^2=\dfrac{1}{9\cdot16}\iff \\\\x^2=\dfrac{1}{144}\iff x=\pm\sqrt{\dfrac{1}{144}}=\pm\dfrac{1}{12}\Longrightarrow\boxed{x=\pm\dfrac{1}{12}}$

$ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\
\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}$

4 0

2 years ago

Line Passing through (4,5) and perpendicular to Equation y= -2x+3

DENIUS [597]

Answer:

1/2x+3

Step-by-step explanation:

I graphed it

3 0

2 years ago