Alright.
For 7, you'll want to put congruent sides equal to each other, assuming they are parallelograms. So, you'll get the two equations:
3x+2=23
2y-7=9
Solve using GEMDAS/PEMDAS, and you'll get these answers.
3x+2=23
3x=21
x=7
2y-7=9
2y=2
y=1
For 8, you'll want to do the exact same thing, formatting the numbers to equal each other. You'll get these two equations:
3y+5=14
2x-5=17
Solving them would make:
3y+5=14
3y=9
y=3
2x-5=17
2x=22
x=11
For 9, you have to remember that the angle opposite of one angle in a defined parallelogram are congruent. Thus:
130=2h
5k=50
solve them and you get
h=65
k=10
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Hope that helped. Good luck.
Answer:
tengo
Step-by-step explanation:
These statements are true:

This is <em>true</em> because of the definition of a rhombus which states that opposite sides are parallel.


This is <em>true </em>because the diagonals of a rhombus bisect each other at right angles.

This is<em> true</em> because the four sides of a rhombus are all equals.

This is also <em>true</em>. Two angles are
supplementary when they add up to 180 degrees. Angles in rhombus are equal two to two. Let's name:
Then it is true that:

Besides, a rhombus is a quadrilateral and it is true that the interior angles of a quadrilateral add up to 360 degrees, thus: