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Rufina [12.5K]
3 years ago
13

Make a decision about the given claim. Use only the rare event​ rule, and make subjective estimates to determine whether events

are likely. For​ example, if the claim is that a coin favors heads and sample results consist of 11 heads in 20​ flips, conclude that there is not sufficient evidence to support the claim that the coin favors heads​ (because it is easy to get 11 heads in 20 flips by chance with a fair​ coin). ​Claim: The mean respiration rate (in breaths per minute) of students in a large calculus class is greater than 15. A simple random sample of the students has a mean respiration rate of 29.5. Choose the correct answer below. A. The sample is unusual if the claim is true. The sample is not unusual if the claim is false.​ Therefore, there is sufficient evidence to support the claim. B. The sample is unusual if the claim is true. The sample is not unusual if the claim is false.​ Therefore, there is not sufficient evidence to support the claim. C. The sample is not unusual if the claim is true. The sample is unusual if the claim is false.​ Therefore, there is sufficient evidence to support the claim. D. The sample is not unusual if the claim is true. The sample is unusual if the claim is false.​ Therefore, there is not sufficient evidence to support the claim.
Mathematics
1 answer:
V125BC [204]3 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

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A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo
never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that \pi = 0.08

98% confidence level

So \alpha = 0.02, z is the value of Z that has a p-value of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}

0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}

\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2

n = 996.3

Rounding up:

A sample of 997 is needed.

3 0
3 years ago
A rectangular poster is to contain 722 square inches of print. the margins at the top and bottom of the poster are to be 2 inche
Delvig [45]
Let
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<span>y ----------> the </span>width<span> of the whole poster
</span>
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we know that
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(y-2)=722/(x-4)
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so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
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find the derivative------> A1 (x)
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for A1(x)=0
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the answer is
<span>the dimensions of the poster will be
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