Answer:
c.
Step-by-step explanation:
Hello!
To take a sample to estimate the mean height of all students at a university and that the value you reach is statistically valid you need the sampling method to be random and representative of the whole population, in this example, all university students.
a. Measure the heights of 50 students found in the gym during basketball intramurals.
This method is not the best because you would be sampling only basketball players leaving all other students of the university outside, i.e. your sample will not be representative of all the students, just the ones that play basketball.
b. Measure the heights of all engineering majors.
This method is not good, the sample only represents engineering mayors meaning that it does not include the students of any other subjects.
c. Measure the heights of the students selected by choosing the first name on each page of the campus phone book.
With this method you choose students regardless of the sport or major they're are taking, it is more representative of the population of university students, of the three options, this is the best one.
I hope it helps!
Answer:
Find the answers below
Step-by-step explanation:
Using m<X as the reference angle
Opposite YZ = 7
Adjacent XY = 10
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinX = opp/hyp
sinX =YZ/XZ
sinX = 7/√149
For cos X
cos X = adj/hyp
cos X =10/√149
Using m<Z as reference angle;
Opposite XY = 10
Adjacent YZ = 7
Hypotenuse XZ = √149
Using the SOH CAH TOA identity
sinZ = opp/hyp
sinZ =10/√149
sinZ = 7/√149
For cos Z
cosZ = 7/√149
<h3>
Answer: Choice B) 45/56</h3>
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Explanation:
When we divide two fractions like this, we flip the second fraction and multiply like so...
which points us to choice B as the answer.
The fraction 45/56 cannot be reduced further because 45 and 56 do not have any factors in common other than 1.
