Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Area of a rectangle: 2(L+W)
length: 4+W
Area: 2(4+W) + 2W = 96
8+2W+2W = 96
8+4W = 96
4W = 88
W= 22cm
Calculate for length: 2L + 2(22) = 96
2L + 44 = 96
2L = 52
L = 26cm
• The length is 26cm and width is 22 cm.
So, put your "x's" together first and then your intercepts. That should answer your question :)
3,000,000+20,000+8,000+2=3,028,002
Also next time, right the numbers with comas please.