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Lubov Fominskaja [6]
3 years ago
6

Please help me solve number 14 and 15

Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

Step-by-step explanation:

Similarity property,

" If the two triangles are similar then their corresponding sides will be proportional."

14). If ΔPQR ~ ΔUVW,

     \frac{PQ}{UV}=\frac{QR}{VW}=\frac{PR}{UW} [Statement}

     \frac{15}{10}=\frac{9}{6}=\frac{6}{4}

     \frac{3}{2}=\frac{3}{2}=\frac{3}{2}  [True}

Therefore, ΔPQR ~ ΔUVW [Theorem - SSS]

15). If ΔFHE ~ ΔDHG,

     \frac{EH}{HG}=\frac{HF}{DH} [Statement]  

     \frac{24}{6}=\frac{36}{9}

     4 = 4

Therefore, ΔFHE ~ ΔDHG [Theorem - AA]

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\cfrac{-15}{6}\implies \stackrel{simplified}{-\cfrac{5}{2}}\impliedby \textit{that's correct, assuming is }\frac{2}{3}~~but~is~~-\frac{2}{3}\\\\
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\bf \stackrel{\textit{recall that minus times minus is plus}}{-\cfrac{11}{6}-\left(-\cfrac{2}{3}  \right)\implies -\cfrac{11}{6}+\cfrac{2}{3}}\implies \cfrac{-(1)11+(2)2}{6}
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