Answer:
A has 263 calories
B has 257 calories
Step-by-step explanation:
system of equations:
a + 2b = 777
2a + b = 783
I multiplied the first equation by -2 to eliminate the 'a' terms
-2a - 4b = -1554
+ <u> 2a + b = 783</u>
-3b = -771
b = 257
solve for 'a'
a + 2(257) = 777
a + 514 = 777
a = 263
<span>8 (3g+2)-3g=3 (5g-4)-2
Multiply the number outside the exponent with the numbers inside the parenthisis.
24g+16-3g=15g-12-2
Subtract 3g from 24g
21g+16=15g-12-2
Add 15g to 21g
36g+16=-12-2
Subtract 2 from -12
36g+16=-14
Subtract 16 from -14
36g=30
Final Answer: g=0.83 (The three goes on infinitely.)
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Answer:
has infinite solution
Step-by-step explanation:
(x,y)=(1-2a,a) where a is an element of any real number
2481.7
^ is the tenth place.
The 5 would either round it up or down by one-tenth. Since we like big numbers... we'll round it to 7 from 6.
