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pashok25 [27]
3 years ago
9

How do you add and subtract fractions??

Mathematics
2 answers:
Serhud [2]3 years ago
7 0
EX:  1/2 + 3/4
Add the top, then add the bottom
Your answer will be 4/6

Same thing with subtracting
1/2 - 3/4
subtract the top, then the bottom
your answer will be 2/2






Semenov [28]3 years ago
5 0
To add fractions they're suppose to have the same base or denominator then u add the top

To subtract it's the same but u subtract the top
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4 years ago
During a three-day period, a provincial hospital received 24 new patients and discharged 6 on the first day, received 8 and disc
IRINA_888 [86]

Answer:

1 : 3

Step-by-step explanation:

Given the following :

First day :

Patient received = 24

Patient discharged = 6

Second day :

Patient received = 8

Patient discharged = 21

First day :

Patient received = 9

Patient discharged = 6

Number of patient in the hospital at the end of the third day:

Patients received = (24 + 8 + 9) = 41

Patients discharged = (6 + 21 + 6) = 33

Patient received - patient discharged

= (41 - 33) = 8

Number of patients in hospital at the start of the three day period :

Patient received on first day = 24

Patient at the end : patient at the start

8 : 24 = 1 : 3

8 0
3 years ago
Yuri has 2/7 of a bag of carrots.if she eats half of the carrots,what fraction of the bag of carrots will she have left
Alisiya [41]
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4 0
3 years ago
A city is holding a referendum on increasing property taxes to pay for a new high school. In a survey of 458 likely voters, 254
aliya0001 [1]

Answer:

The confidence interval is -5.3444 to 6.453 .

Step-by-step explanation:

We are given that  In a survey of 458 likely voters, 254 said that they would vote "yes" on the referendum.

So, n = 458

x = 254

We will use sample proportion over here

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{254}{458}

\widehat{p}=0.5545

Confidence level = 95% = 0.95

Level of significance = 1-0.95 = 0.05

z value at 0.05 significance level = 1.96

Formula of confidence interval : \widehat{p}-x\times \sqrt{\frac{\widehat{p} \times (1-\widehat{p})}{n} to \widehat{p}+x\times \sqrt{\frac{\widehat{p} \times (1-\widehat{p})}{n}

Confidence interval : 0.5545-254\times \sqrt{\frac{0.5545\times (1-0.5545)}{458}} to 0.5545+254\times \sqrt{\frac{0.5545\times (1-0.5545)}{458}}

Confidence interval : -5.3444 to 6.453

Hence The confidence interval is -5.3444 to 6.453 .

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3 years ago
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The slope is 3/2 (use rise over run)
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