D = M/V where M=mass and V = volume
Assume the Mass is 1 kg and the Volume = 1 cm³, so d= 1/1 kg/cm³
for V=0.1 → d = 1/0.1 = 10 kg.cm³
for V = 0.01 → d = 100.kg.cm³
for V = 0.001 → d = 1000.kg.cm³
for V = 0.000001 → d = 1,000,000.kg.cm³
and when Volume → 0. density →∞
.
No because he will be $3.00 short.
So it is $0.75 a bottle. So then you multiply $0.75 by 20. You get $15.00
So David will not have enough in his wallet.
Answer:
See below
Step-by-step explanation:
<u>Given function:</u>
m represents the domain and D represents the range of the function, therefore m = x, D = y
<u>Filling in the table:</u>
- for x = 10, y = 35 + 0.4*10 = 35 + 4 = 39 and so on for the rest of the values
- x = 10, 30, 50, 75, 100
- y = 39, 47, 55, 65, 75
let's firstly convert the mixed fractions to improper fractions and then divide.
![\bf \stackrel{mixed}{17\frac{13}{18}}\implies \cfrac{17\cdot 18 +13}{18}\implies \stackrel{improper}{\cfrac{319}{18}}~\hfill \stackrel{mixed}{2\frac{7}{9}}\implies \cfrac{2\cdot 9+7}{9}\implies \stackrel{improper}{\cfrac{25}{9}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B17%5Cfrac%7B13%7D%7B18%7D%7D%5Cimplies%20%5Ccfrac%7B17%5Ccdot%2018%20%2B13%7D%7B18%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B319%7D%7B18%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B7%7D%7B9%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%209%2B7%7D%7B9%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B25%7D%7B9%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \cfrac{319}{18}\div \cfrac{25}{9}\implies \cfrac{319}{\underset{2}{~~\begin{matrix} 18 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{1}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{25}\implies \cfrac{319}{50}\implies 6\frac{19}{50}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B319%7D%7B18%7D%5Cdiv%20%5Ccfrac%7B25%7D%7B9%7D%5Cimplies%20%5Ccfrac%7B319%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%2018%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B%5Cstackrel%7B1%7D%7B~~%5Cbegin%7Bmatrix%7D%209%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%7B25%7D%5Cimplies%20%5Ccfrac%7B319%7D%7B50%7D%5Cimplies%206%5Cfrac%7B19%7D%7B50%7D)
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10