All categories

3 years ago

What is the volume of a rectangle prism with a height of 4 yards and a base with the area 16 yards

Mathematics

1 answer:

Reil [10]3 years ago

8 0

Answer:

64 ft^2

Step-by-step explanation:

4*16

You might be interested in

The rectangle shown is enlarged such that each side is multiplied by the value of the width, 2x. Which expression represents the

kykrilka [37]

Answer:

<h2> The answer is </h2><h2> D. 8x^2+4xy</h2>

Step-by-step explanation:

We know that the expression for the perimeter is given as

P=2l+2B

now given that the value of the width is =2x

length= 4x

and the breadth=y

P=4x+2y

let us multiply both the length and the width with 2x we have

P=2x(4x+2y)

P=8x^2+4xy

the answer is

D. 8x^2+4xy

4 0

4 years ago

The gates of an amusement park are closely monitored to determine whether the number of

fredd [130]

Answer:

Maybe how many people are in the park

3 0

3 years ago

There are 180 cars in the parking lot 30% are red cars how many red cards are there

Yuri [45]

There are 54 red cars

7 0

2 years ago

Read 2 more answers

Evaluate Ic2 + b2l, given a = 5, b = -3, and c= -2.

LenKa [72]

Answer:

Ic² + b²l = 13 units.

Step-by-step explanation:

We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

Now, Ic² + b²l

= I(- 2)² + (- 3)²l {Putting the values of b and c}

= I4 + 9l

= I13l

= 13 units.

Therefore, Ic² + b²l = 13 units. (Answer)

5 0

3 years ago

Descried how to derive the quadratic formula from a quadratic equation in standard form

Aleks [24]

Answer:

The standard form of a quadratic equation is:

$ax^2+bx+c=0$ , $a\neq 0$

Quadratic Formula Derivation:

$ax^2+bx+c=0\\$

$x^2+\frac{b}{a}x+\frac{c}{a} =0$

$x^2+\frac{b}{a}x = -\frac{c}{a}$

Completing the Square:

$x^2+\frac{b}{a}x +\frac{b^2}{4a^2} = \frac{b^2}{4a^2}-\frac{c}{a}$

$( x+\frac{b}{2a} )^2 = \frac{b^2-4ac}{4a^2}$

Square Root property:

$x+\frac{b}{2a} = \pm \sqrt{ \frac{b^2-4ac}{4a^2}}$

$x = -\frac{b}{2a} \pm { \frac{\sqrt {b^2-4ac}}{2a}}$

$x = \frac{-b\pm\sqrt{b^2-4ac}} {2a} }$

8 0

3 years ago