32.5 square feet. If you do the area formula “A=5v13(13) over 2”
<u>Answer:</u>
8 meters or 4 meters
<u>Step-by-step explanation:</u>
We know that for finding the area of a rhombus, there are two diagonal sides: one of which is 12.5 meters in length and the other one we'll assume to be y.
Then, we can write:
Area of rhombus =
![50=\frac{1}{2} *12.5*y](https://tex.z-dn.net/?f=50%3D%5Cfrac%7B1%7D%7B2%7D%20%2A12.5%2Ay)
![y=\frac{100}{12.5}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B100%7D%7B12.5%7D)
meters
If the sides of the rhombus are not internally diagonal, then we can simply use the following formula:
Area of rhombus = altitude * side
![50=a*12.5](https://tex.z-dn.net/?f=50%3Da%2A12.5)
meters
Answer:
3
Step-by-step explanation:
I believe it is 3 because you are multiplying each number by 3 to get your bigger shape
So the annual rate is 7% (0.07). The account starts with $50. The money sits in there untouched for 8 years.
1. 50 * 0.07 = 3.5
50 + 3.5=53.5
2. 53.5 * 0.07 = 3.745
53.5 + 3.745 = 57.245
3. 57.245 * 0.07
Now you do the rest. I did up to year two for you, go ahead and complete the rest by yourself. If you have questions please ask I would love to help. :)
Answer:
For a height of 66 inches, Z = 0.65.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The average height was about 64.3 inches; the SD was about 2.6 inches.
This means that ![\mu = 64.3, \sigma = 2.6](https://tex.z-dn.net/?f=%5Cmu%20%3D%2064.3%2C%20%5Csigma%20%3D%202.6)
66 inches:
The z-score for a height of 66 inches is:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{66 - 64.3}{2.6}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B66%20-%2064.3%7D%7B2.6%7D)
![Z = 0.65](https://tex.z-dn.net/?f=Z%20%3D%200.65)
For a height of 66 inches, Z = 0.65.