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Furkat [3]
3 years ago
5

A small start-up company with 16 employees will select its 4 board members from among the employees. How many different groups o

f board members are possible?
Mathematics
1 answer:
Mashcka [7]3 years ago
5 0
16 divided by 4 is 4
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What # divided by what # equals -7
creativ13 [48]
7 divided by -1 equals -7
7 0
3 years ago
I need help with this one math question please!
den301095 [7]

Answer:

see explanation

Step-by-step explanation:

Assuming the fractions are being multiplied

Factorise the denominators of both fractions

x² - 3x - 10 = (x - 5)(x + 2)

x² + x - 12 = (x + 4)(x - 3)

The product can now be expressed as

\frac{x-5}{(x-5)(x+2)} × \frac{x+2}{(x+4)(x-3)}

Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving

\frac{1}{(x+4)(x-3)} = \frac{1}{x^2+x-12}

3 0
3 years ago
A square rug has an inner square in the center. The side length of the inner square is x inches and the width of the outer regio
Gwar [14]

Answer: area of the outer part of the​ rug= 16 -x²

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a square: Side²

Since the area of the rug including the inner square is:  

Area of the rug = 4² =16 in²

And the area of the inner square is equal to:

Area if the inner square = x²

To obtain the area of the outer part of the rug we have to subtract the area of the inner square to the area of the rug.

Area of the outer part of the rug= 16 -x²

Feel free to ask for more if needed or if you did not understand something.

6 0
3 years ago
How to find the zeros of f(x)=5(2x-5)(5x+4)
Elenna [48]
If xy=0 we assume x and y equal 0

so

the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that

0=2x-5
5=2x
5/2=x

0=5x+4
-4=5x
-4/5=x

zeroes at x=5/2 and -4/5
3 0
3 years ago
Read 2 more answers
Which of the following square root of -80
Marta_Voda [28]

You can factor -80 as

-80 = (-1)\cdot 16 \cdot 5

So, we have

\sqrt{-80} = \sqrt{(-1)\cdot 16 \cdot 5}

The square root of a product is the product of the square roots:

\sqrt{-80} = \sqrt{(-1)}\sqrt{16}\sqrt{5}

Since i^2=-1 and 4^2=16, we have

\sqrt{-80} = 4i\sqrt{5}

8 0
3 years ago
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