Answer:
here
Step-by-step explanation:
Create a system if equations to solve this.
First equation:
25m + 24e = 220
Second equation:
m + e = 9
Then you must solve the second equation for a variable.
Change m + e = 9 to e = 9 - m.
Then substitute (9 - m) for e in the first equation.
So 25m +24e = 220 becomes 25m + 24(9 - m) = 220.
Now you can solve the first equation because the only variable in it is m.
25m + 24(9 - m) = 220 (Original equation)
25m + 216 - 24m = 220 (Distribute)
m + 216 = 220 (Combine like terms)
m = 4 (Simplify)
Now plug in 4 for m in the second equation.
m + e = 9 (Original equation)
(4) + e = 9 (Substitute)
e = 5 (Simplify)
m represents Math Books and e represents English Books, so Nicole purchased 4 Math Books and 5 English Books.
So first, you subtract 9 and 4, which gives you 5. Then, you add that to 5. That gives you 10.
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
Answer:
15) 20.4
16) 40.4
17) 2.5
18) 32
Step-by-step explanation:
15) Use the calculator: 42.7/11.1*5.3
16) Use the calculator: 121.1/3
17) Use the calculator: 32.5/ (42.9/3.3)
18) 28.8/ (1.8/2)
