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3 years ago

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The diameter of the raw cookie is 2 1 2 inches. After baking the cookie, the diameter is 5 1 2 inches. By what factor does the c

ookie expand? A 236% B 220% C 45% D 42%

2 answers:

Scorpion4ik [409]3 years ago

8 0

Answer:

220%

Step-by-step explanation:

to the test got answer correct

elena-14-01-66 [18.8K]3 years ago

3 0

Answer:

120%

Step-by-step explanation:

Given that,

The diameter of the raw cookie is 2 1/2 inches i.e. 5/2 inches

After baking the cookie, the diameter is 5 1/2 inches i.e. 11/2inches

We need to find by what factor does the cookie expand.

$x=\dfrac{5\dfrac{1}{2}-2\dfrac{1}{2}}{2\dfrac{1}{2}}\times 100\\\\=\dfrac{\dfrac{11}{2}-\dfrac{5}{2}}{\dfrac{5}{2}}\times 100\\\\=120\%$

So, the cookie will expand 120%.

You might be interested in

Find the equation of a line passing through the point(-3,0) and (2,-3)

Svetradugi [14.3K]

Answer <u>(assuming the question allows it to be written in slope-intercept form)</u>:

$y = -\frac{3}{5} x-\frac{9}{5}$

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula $m = \frac{y_2-y_1}{x_2-x_1}$ , substitute the given points' x and y values, and simplify:

$m = \frac{(-3)-(0)}{(2)-(-3)} \\m =\frac{-3-0}{2+3}\\m = -\frac{3}{5}$

Thus, the slope is $-\frac{3}{5}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ and substitute real values for $m$ , $x_1$ , and $y_1$ .

Since $m$ represents the slope, substitute $-\frac{3}{5}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:

$y-(-3) = -\frac{3}{5} (x-(2))\\y + 3 = -\frac{3}{5} x + \frac{6}{5} \\y = -\frac{3}{5} x - \frac{9}{5}$

5 0

3 years ago

Read 2 more answers

What is the difference?

Serhud [2]

Answer:

The option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

The difference of the given expression is

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Step-by-step explanation:

Given expression is $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

To find the difference of the given expression as below :

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-9)})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-3^2)})-({\frac{x+1}{x^2-3^2})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x-3)(x+3)})-({\frac{x+1}{(x-3)(x+3)})$

( using the formula $a^2-b^2=(a+b)(a-b)$ )

$=\frac{2x+5(x+3)-(3x+5)-x(x+1)}{x(x-3)(x+3)}$

$=\frac{2x^2+6x+5x+15-3x-5-x^2-x}{x(x-3)(x+3)}$ (adding the like terms)

$=\frac{x^2+7x+10}{x(x^2-9)}$ ( by factoring the quadratic polynomial )

$=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore the difference of the given expression is

$\frac{(x+5)(x+2)}{x^3-9x}$

Therefore option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

8 0

3 years ago

Andre drew a plan of a courtyard at a scale of 1 to 60. On his drawing, one side of the courtyard is 2.75 inches. What is the ac

ch4aika [34]

Answer:

It’s larger

Step-by-step explanation:

4 0

4 years ago

Two circles with the same center are congruent sometimes, always, or never ?

love history [14]

I would go with Never because you would have to have two circles with a different center to be congruent

6 0

4 years ago

-2/3 ( -12x + 15) = 12

Afina-wow [57]

Answer:

x=11/4=2.75

Step-by-step explanation:

8x-10=12

8x=22

x=22/8=11/4=2.75

8 0

3 years ago

Read 2 more answers