Not a question. Please refrain from unnecessary post.
Answer:
a. Heterozygous individuals may pass on their copy of the disease-causing allele to offspring.
Explanation:
Tay-Sachs, which is a recessive lethal disease ---- Let say the recessive lethal diseases is s
∴ it only results when an individual posses two copies of the diseases-causing allele i.e two copies of the disease will be ss.
Now, when two hetrozygous individuals crossed , it is obvious that each can pass on their copy of the disease-causing allele to the offspring.
Let show an illustration for the above statement.
Let the heterozygous individual be Ts, if Ts cross with another Ts;
we will have:
Ts × Ts
T s
T TT Ts
s Ts ss
the offspring are TT,Ts,Ts,ss
We can now see how the Heterozygous individuals pass on their copy of the disease-causing allele to the offspring (Ts).
Out of the choices given, active and passive transport of solutes across a membrane typically differ because active transport always involves the utilization of cellular energy, whereas passive transport does not require cellular energy. The correct answer is B.
The cross between parent plants if one is heterozygous for yellow pods and the other is homzygous for green pods - Yy yy., i.e., option A.
<h3>What is heterozygous?</h3>
The occurrence of different types of alleles is referred to as heterozygous condition.
A heterozygous genotype may consist of one normal allele and one mutated allele, or two distinct mutated alleles.
The missing options of the question are:
- Yy ´ yy
- YY ´ yy
- Yy ´ Yy
- yy ´ yy
The cross between parent plants if one is heterozygous for yellow pods and the other is homzygous for green pods - Yy yy.
Thus, the correct option is A.
For more details regarding heterozygous genotype, visit:
brainly.com/question/238628
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