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2 years ago

Please answer very confuse english very bad que?

Mathematics

1 answer:

nata0808 [166]2 years ago

4 0

Answer:

for the first question, it's (2,2) and for the last question it's (0,2)

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Scientists notice two asteroids moving directly toward each other. Right now, they are 20 million kilometers apart, but they are

ruslelena [56]

Answer:

The point of intersection is (6, 8). This indicates that in 6 days, asteroid A and B will collide at a point that is 8 million miles away from asteroid A's current position and 12 million miles away from asteroid B's current position.

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2 years ago

Read 2 more answers

What is the ratio of 3 cans of blue paint to 9 cans<br> of yellow paint

Phoenix [80]

Answer:

1 to 3

Step-by-step explanation:

3 blue: 9 yellow

Divide each side by 3

3/3 : 9/3

1 blue: 3 yellow

1 to 3

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2 years ago

Help Are the triangles similar? If so, determine the scale factor of ΔPQR to ΔEFD.

alex41 [277]

The answer is B.
When you set up a ratio of all the corresponding sides, the ratios all equal 2:1

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3 years ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

2 years ago

WORTH 50 POINTS!!

cluponka [151]

Answers: Choice A and Choice E

0.82B and B-0.18B

========================================================

Explanation:

B is the cost of the game (some unknown amount). Subtract off 0.18B to indicate a 18% reduction in the price. That's how we get choice E.

Simplifying choice E leads us to choice A. Notice that 1 - 0.18 = 0.82; which represents 100% - 18% = 82%. After the discount, Bo is paying 82% of the original price.

Side note: Choice B indicates an 18% increase. Choices C and D don't represent percentage decreases (rather they're decreasing by a fixed amount regardless of what B is).

4 0

1 year ago