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alisha [4.7K]
2 years ago
15

I need it within tomorrow please

Mathematics
1 answer:
Alenkinab [10]2 years ago
6 0

Any even number raised to any power will remain even. (e.g. 2² = 4, 2³ = 8, etc)

Any odd number raised to any power will remain odd. (e.g. 1² = 1³ = ... = 1, 3⁴ = 81, etc)

So (n+1)^{2^k}-n^{2^k} will always be even, since both

[even] - [odd] = [odd]

and

[odd] - [even] = [odd]

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