Question

Don and Marie like to go to a good restaurant. Dinners are $16 to $19 dollars with soup or salad. A beverage is $1.50. Dessert is $3.75. If one dinner is $16, the other is $19 and each diner has a beverage and dessert, what will the cost be if a 6% tax is charged and a 15% tip on the pre-tax amount is left?

Answer 1

Hi there!

The correct answer is calculated like so:

16 + 19 + 3 + 3.75 + 3.75 = 45.5

45.5 * 0.06 = 2.73

45.5 * 0.15 = 6.83

45.5 + 2.73 + 6.83 = $55.06

Your friend, ASIAX

Answer 2

Answer: $55.055

Step-by-step explanation:

The cost of one dinner = $16+$1.50+$3.75=21.25

The cost of the other dinner = $19+$1.50+$3.75=24.25

The total cost of both the dinners = $21.25+24.25=\ \ 45.5$

The 15% tax on the cost of dinners = $0.15\times45.5=\ \ 6.825$

The 6% tax on the dinners =$0.06\times45.5=\ 2.73$

The total cost of the dinners =$\ \ 45.5+\ \ 6.825+\ \ 2.73=\ 55.055$

The cost of dinners if a 6% tax is charged and a 15% tip on the pre-tax amount is left =$55.055