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Taya2010 [7]
4 years ago
14

Hellppppppppppppppppppppppppp

Mathematics
1 answer:
Ivenika [448]4 years ago
7 0

Im pretty sure the awnser is

3.300

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What is the speed of each
elena-s [515]

the rates of change will be 210. if the change is after 8 hours than the rate of change will be 105

7 0
3 years ago
A water sprinkler sprays water over a distance of 36 feet while rotating through an angle of 140 degrees. What area of lawn rece
aniked [119]

Answer: 1,583.36\ ft^2

Step-by-step explanation:

The formula for calculate the area of a Sector of a circle is:

A=\pi r^2(\frac{C}{360})

Where "C" is the central angle in degrees and "r" is the radius.

Based on the data given in the exercise, you can identify that:

r=36\ ft\\C=140\°

(See the figure attached)

Then, you can substitute these values into the formula and then evaluate, in order to calculate the area of lawn that receives​ water.

The result is:

A=\pi r^2(\frac{C}{360})\\\\A=\pi (36\ ft)^2(\frac{140\°}{360})\\\\A=1,583.36\ ft^2

4 0
3 years ago
What is the answer to<br> (-6x-6)+(8x-6)
Otrada [13]
(-6x-6)+(8x-6)
-6x-6+8x-6
2x-12

Hope this helps :)
8 0
3 years ago
When p2 – 4p is subtracted from p2 + p – 6, the result is 5p-6 To get p – 9, subtract
jeka57 [31]
(p^{2}  + p - 6) - (x) = p - 9&#10;&#10; is what is asked.

So all you need to do is a value that will result to p - 9.

x = (p^{2} + p - 6) - p + 9  To isolate x we just transpose the values from the other side of the equation and do the opposite operation. 

Combine like terms and just copy the terms that do not have similar expressions:

p will cancel out because p - p = 0
-6 and + 9  will come together because they are like terms: -6 + 9 = 3 
p^{2} does not have a pair so it will remain as is. you will be left with:

p^{2}  + 3

Let us check:

   p^{2} + p - 6
-  p^{2} + 0 + 3  
----------------------------
   0 + p - 9    or p -9               
6 0
4 years ago
Read 2 more answers
A–2=3+6a/3<br> What dose a equal?
balandron [24]

Answer:

a = -5

Explanation:

7 0
3 years ago
Read 2 more answers
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