Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides, and . A 95% large-sample CI for the true average percentage elongation is given by , i.e., or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
Answer:
c = 9
Step-by-step explanation:
9c - 10 = 2c + 53
9c =2c + 63
7c = 63
c = 9
Answer:
Step-by-step explanation:
The solution is attached