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3 years ago

Can i get help please with this math question

Mathematics

1 answer:

strojnjashka [21]3 years ago

3 0

Answer:

Step-by-step explanation:

1.25 is incorrect becuase 25% is .25 not 1.25

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Solve: the quantity 2x minus 20 divided by 3 = 2x

ira [324]

Answer:

x=-5

Step-by-step explanation:

$\dfrac{2x-20}{3}=2x$

Multiply both sides by 3:

$2x-20=6x$

Subtract 2x from both sides:

$-20=4x$

Divide both sides by 4:

$x=-5$

Hope this helps!

6 0

3 years ago

Read 2 more answers

Find the values of a and b such that x^2 + 3x + 4 = (x + a)^2+ b

sesenic [268]

Answer:

$x {}^{2} + 3x + 4 = (x + a) {}^{2} + b \\ x {}^{2} + 3x + 4 = x {}^{2} + 2ax + a {}^{2} + b \\ = x {}^{2} + a {}^{2} + 2ax + b \\ 2a = 3 \\ b = 4 \\ a = \frac{3}{2} \\ b = 4$

8 0

3 years ago

A rectangular solid has a base with length 2 centimeters and a width of 8 centimeters. If the volume of the solid is 160 centime

Whitepunk [10]

10 centimeters it is 160/8=20/2=10

8 0

4 years ago

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

Read 2 more answers

Please show your work! I have 3 more of these, and I want to be able to do them by myself.

Radda [10]

Answer:

Step-by-step explanation:

We group the number 5:

5(x² + 3x + 2.25)

Now inside the brackets we'll take the square root of the coefficient of the x and the square root of the last number, then remove the square from the x and write it as a sum:

5(x+1.5)²

What's the idea behind this?

Well, remember that when you have something in the form:

(a+b)²

It actually means:

a² + 2ab + b²

In our case a was x, and b was 2.25. For bringing it into the shorter form we have to take the square root of a and b.

Sorry if you don't understand. Tell me if you need help to get the xoncept better.

3 0

2 years ago