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2 years ago

Find the ratio to 2.5 cups of water to 1.5 cups of milk

Mathematics

1 answer:

zaharov [31]2 years ago

6 0

Answer:

2.5 : 1.5 is the ratio

Step-by-step explanation:

2.5 cups of water to 1.5 cups of milk

2.5 to 1.5

2.5:1.5

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Would 0=0 be no solution to a system? Yes or No

denis-greek [22]

No, 0=0 has an infinite amount of solutions.

3 0

2 years ago

Read 2 more answers

Do you guys the answer for number 3

ohaa [14]

Answer:

the answer is L. or the last answer

Step-by-step explanation:

you have to find the total area of the place first...

which is 21*17=357

then subtract the inner area (white area) which is

14*20=280

do 357-280 to get the remaining area and the answer is 77ft^2

hope this helps.. vote, comment, thanks, and maybe mark me brainliest lol idk

3 0

3 years ago

In a class of 10, there are 5 students who play soccer.

Ipatiy [6.2K]

Answer:

Step-by-step explanation: 5/10=1/2 - if one student are chosen, who plays soccer

4/9 if then the second student are chosen, who plays soccer

1/2*4/9=2/9 the probability that both students play soccer

3 0

2 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

Step 2: Find Right-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

Step 3: Find Left-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ Since $\displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)$ , then $\displaystyle \lim_{x \to 5} f(x) = DNE$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

2 years ago

Simplify x raised ^ 5 x - 2

MaRussiya [10]

The property x^axb makes it x^a+b so x^5x-2 ,

Therefore x^-10 is final

5 0

2 years ago