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Olegator [25]
3 years ago
6

A number is chosen at random from 1 to 25. Find the probability of selecting an odd number or multiple of 5.

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
5 0
16\25 (my guess)
Because there is 13 odd numbers and 3 is a multiple of 5 so i added 13+3=16
16 out of 25 options

Sauron [17]3 years ago
4 0
Odd number probability: 13/25 Multiple of five probability: 4/25
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Option (4)

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kirza4 [7]

Answer:

Formula used :

  • <u>x²+2xy+y²</u><u> </u><u>=</u><u> </u><u>(x+y)²</u>
  • <u>x²-2xy+y²</u><u> </u><u>=</u><u> </u><u>(x-y)²</u>

→{x}^{2}  + 6x +  {y}^{2}  - 8y = 19 \\  ({x}^{2}  + 2.3.x +  {3}^{2} ) +({y}^{2}  - 2.4.y +  {4}^{2} ) = 19 +  {3}^{2}  +  {4}^{2}  \\  {(x + 3)}^{2}  +  {(y - 4)}^{2}  = 19 + 9 + 16 \\  \boxed{ {(x + 3)}^{2}  +  {(y - 4)}^{2}  = 44}✓

  • <u>3) (x+3)²+(y-4)²=44</u> is the right answer.
8 0
3 years ago
Read 2 more answers
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