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allochka39001 [22]
3 years ago
14

Find the equation of the line passing

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0
Rearrange the formula given to determine the slope, you will see that in y=mx+b form the slope is -2/3
You now have the slope (m) and two test points. Input those values into y=mx+b and you will have your answer!
I got y=(-2/3)x+(22/3) which I'm quite certain is correct.
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Free for all<br> gl<br> :) dun dun DUN
erastovalidia [21]

Answer:

Step-by-step explanation:

TYSM

HAVE A GREAT DAY

5 0
2 years ago
Helppp plsssss!!show your work.<br>Thanks
gregori [183]

You are basically just adding, so combine like terms.

3x^2 + 5x^2 = 8x^2

6x - 2x = 4x

4 - 8 = -4

So the answer is D.

8 0
3 years ago
Read 2 more answers
Please help me with the problem
mixas84 [53]
Let's see what we're working on here 

\frac{1}{2}  - 2(m) =?
            ? = 0
Simplify this → \frac{1}{2}

\frac{1}2y} - 2(m) = ?

\frac{2(m)(2)}{2}

\frac{1 - 4(m)}{2} = ?

\frac{1 - 4(m)}{2} = 2

-4(m) + 1 = 0
 Subtract ( - )the number 1 from each of your sides on this part

4(m) = 1 
Multiply( ×) the number -1 to your sides for this part of the equation 

Therefore, the value of m is \frac{1}{4}
m =  \frac{1}{4}


3 0
3 years ago
Read 2 more answers
Figure EFGHK is to be transformed to Figure E'F'G'H'K' using the rule (x, y)→(x + 8, y + 5):
IceJOKER [234]
The rule that has been given means that x coordinate of some point we increase by 8 and y coordinate of some point we increase by 5.

Coordinates of K point on original Figure are:
(-2,-3)

once we implement rule on this we get K':

K' ( -2+8,-3+5) 
or 
K' ( 6,2)

Answer is third option.

8 0
3 years ago
Read 2 more answers
Solve this system of equations by any method.<br> 5x + y = -13<br> 4x + 3y= -17
irga5000 [103]
5x + y = -13.....multiply by -3
4x + 3y = -17
-----------------
-15x - 3y = 39 (result of multiplying by -3)
4x + 3y = -17
-----------------add
-11x = 22
x = -22/11
x = -2

5x + y = -13
5(-2) + y = -13
-10 + y = -13
y = -13 + 10
y = -3

solution (-2,-3)
5 0
3 years ago
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