There are 21 black socks and 9 white socks. Theoretically, the probability of picking a black sock is 21/(21+9) = 21/30 = 0.70 = 70%
Assuming we select any given sock, and then put it back (or replace it with an identical copy), then we should expect about 0.70*10 = 7 black socks out of the 10 we pick from the drawer. If no replacement is made, then the expected sock count will likely be different.
The dot plot shows the data set is
{5, 5, 6, 6, 7, 7, 7, 8, 8, 8}
The middle-most value is between the first two '7's, so the median is (7+7)/2 = 14/2 = 7. This can be thought of as the average expected number of black socks to get based on this simulation. So that's why I consider it a fair number generator because it matches fairly closely with the theoretical expected number of black socks we should get. Again, this is all based on us replacing each sock after a selection is made.
H = 151t - 16t²
The height of the ball when it return to the ground will be 0
0 = 151t - 16t²
The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0 or 16t - 151 = 0
So t = 0 or t = 9.44 seconds
The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
2x + 1.5x +20 = 90
3.5 x = 90-20
3.5 x = 70
x = 70/3.5
x = 20
angle DAE = 2*20 = 40
angle CAD = 1.5*20 +20 = 50
Answer:
x=12
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.