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Xelga [282]
4 years ago
13

10 POINTS!! Fast!! In the figure, (BE)||(CD). Solve for x. Show your work.

Mathematics
1 answer:
KatRina [158]4 years ago
6 0

AE/ED=AB/BC

9/6=x/10

x=15

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A rocket is launched from a height of 3m with an initial velocity of 15 m/s at what time will the rocket be 13m from the ground?
dem82 [27]
Not sure of my answer but, velocity=delta d/delta t. t=delta d/ velocity
—> t=(13-3)/15=>10/15=2/3s
4 0
2 years ago
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
What is the value of x in the equation 3- 2x = -1.5х?
Vika [28.1K]

Answer:

x = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

3 - 2x = -1.5x

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 2x on both sides:                    3 = 0.5x
  2. Divide 0.5 on both sides:               6 = x
  3. Rewrite:                                           x = 6

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in<em> x</em>:                    3 - 2(6) = -1.5(6)
  2. Multiply:                               3 - 12 = -9
  3. Subtract:                              -9 = -9

Here we see that -9 does indeed equal -9.

∴ x = 6 is the solution to the equation.

6 0
3 years ago
Read 2 more answers
Four people in a room. Each shakes hands with each of the others once. How many handshakes are there?
storchak [24]
<span>The correct answer is 6.

The clearest way to determine this is by creating a table of possible hand shaking. If we label the people A-D, the following are the ways they can be combined:
AB
AC
AD
BC
BD
CD

There are no other combinations. </span>
7 0
3 years ago
Read 2 more answers
It took Jimena 89 minutes to run a 15-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minu
Novosadov [1.4K]
The answer is <span>9.55 minutes
</span>
1. Turn 15 km into miles:
    1 km = 0.621 mile
    15 km = 15 * 0.621 mile = 9.315 miles
So, she ran 9.315 miles for 89 minutes

2. Calculate <span>how many minutes it took Jimena to run 1 mile during the race:
    S</span>he ran 9.315 miles for 89 minutes.
    She ran 1 mile for x minutes.
    9.315 mi : 89 min = 1 mi : x
    x = 89 min * 1 mi / 9.315 mi
    x = 9.55 min
3 0
3 years ago
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