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Tcecarenko [31]
3 years ago
12

Solve the rational equation 4/x=3x+2/x^2, and check for extraneous solutions.

Mathematics
1 answer:
Aleks [24]3 years ago
4 0

Answer:

x = 2 is a solution

x = 0 is an extraneous solution

(Option 2)

Step-by-step explanation:

4/x = (3x + 2)/x²

4x² = 3x² + 2x

x² - 2x = 0

x(x - 2) = 0

x = 0, x = 2

Verification:

4/x = (3x + 2)/x²

At x = 2

4/2 = [3(2) + 2]/2²

2 = 8/4

2 = 2

At x = 0

4/0 = [3(0) + 2]/0²

Is undefined

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FinnZ [79.3K]
The answer is a because i said so.
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nickel has an approximate diameter of 20 mm and an approximate thickness of 2 mm what is the approximate volume of a stack of 40
ziro4ka [17]

Answer:

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

Step-by-step explanation:

A nickel can be modelled by the formula of a right cylinder, the approximate volume of the stack of nickels (V_{net}), measured in cubic milimeters, is the product of the number of elements (n), no unit, and the volume of each element (V), measured in cubic milimeters. That is:

V_{net} = n\cdot V (1)

By volume equation of right cylinder, we have the following formula:

V_{net} = \frac{\pi}{4}\cdot n \cdot D^{2}\cdot h (2)

Where:

n - Amount of nickels, no unit.

D - Diameter of nickel, measured in milimeters.

h - Thickness of nickel, measured in milimeters.

If we know that n = 40, D = 20\,mm and h = 2\,mm, then the net volume of the stack of nickels is:

V_{net} = \frac{\pi}{4}\cdot (40)\cdot (20\,mm)^{2}\cdot (2\,mm)

V_{net} \approx 25132.741\,mm^{3}

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

8 0
2 years ago
Find the sample size, n, needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.02 margin of er
Brrunno [24]

Answer: 2172

Step-by-step explanation:

Formula to find the sample size n , if the prior estimate of the population proportion(p) is known:

n= p(1-p)(\dfrac{z^*}{E})^2 , where E=  margin of error and z* = Critical z-value.

Let p be the population proportion of adults have consulted fortune tellers.

As per given , we have

p= 0.20

E= 0.02

From z-table , the z-value corresponding to 98% confidence interval = z*=2.33

Then, the required sample size will be :

n= 0.20(1-0.20)(\dfrac{2.33}{0.02})^2

n= 0.20(0.80)(116.5)^2

n= 2171.56\approx2172

Hence, the required sample size = 2172

3 0
2 years ago
The quotient of two numbers is 3 and their sum is 8 what are he two numbers
Nezavi [6.7K]
<h2>Translating Word Equations into Numerical Equations</h2>

To change words into equations, we can recognize keywords that translate into operations and/or numbers:

  • <em>quotient</em> = divide
  • <em>a number/the number/two numbers</em> = variables
  • <em>sum</em> = add

<h2>Solving the Question</h2>

Let the two numbers be <em>a</em> and <em>b</em>.

We're given:

  • quotient of <em>a</em> and <em>b</em> is 3
    ⇒ \dfrac{a}{b}=3
  • sum of <em>a</em> and <em>b</em> is 8
    ⇒ a+b=8

First, isolate <em>a</em> in the first equation and substitute it in the second equation to solve for <em>b</em>:

\dfrac{a}{b}=3\\\\a=3b

a+b=8\\3b+b=8\\4b=8\\b=2

Therefore, one of the numbers is 2. Substitute this into one of our equations to solve for <em>a</em>:

a+b=8\\a+2=8\\a=6

Therefore, the other number is 6.

<h2>Answer</h2>

The two numbers are 2 and 6.

4 0
1 year ago
Can someone help me with this question?
notsponge [240]
The answer is forty inches
3 0
3 years ago
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