Answer:
y= -2x+18
Step-by-step explanation:
1. The secant line is a line that passes through 2 points in the function.
2. Determine the y values for x=-6 and x=3 by plugging the x values into the x^2 + x function. This yields 30 for x=-6 and 12 for x=3.
3. Find the slope by calculating the rise over the run, represented by the equation (y2 - y1)/(x2-x1). Plugging in the numbers we get (12-30) divided by (3 -(-6)). This gives you a slope equation of -18/9 (subtracting a negative yields a positive), which simplifies to -2.
4. Now that you have your slope m, apply it backwards from x=3 (x=2 yields 14 for y, 1 yields 16, 0 yields 18). Once you arrive at x=0, the y value is your y-intercept.
5. Put the y-intercept b into the equation y= mx+b, and you come out with y= -2x + 18!
Exact form: 1/4 Decimal form: 0.25
Hello from MrBillDoesMath!
Answer: 6 u^2 + 4u + 6 = 0 where u = (x-5)^2
Discussion; I think the problem statement should actually be to rewrite <u>this</u> equation:
6 (x-5)^4 + 4 (x-5)^2 + 6 -= 0.
Note the power of "x-5" is 4 in the first term and is 2 in the second term. That is, the power of x-5 in the first terms is double, or the square, of the (x-5) power occurring in the second term. This suggest the substitution u = (x-5)^2. Then the equation can be rewritten as
6 u^2 + 4u + 6 = 0
which is a quadratic in "u".
Regards, MrB
