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alisha [4.7K]
3 years ago
11

On Saturday Keisha ran 3.218 kilometers. on Sunday she ran 2.41 kilometers. How much further did she run on Saturday than on Sun

day
Mathematics
2 answers:
Len [333]3 years ago
7 0
0.808 km, you find the difference between the two numbers
worty [1.4K]3 years ago
7 0

Answer:

0.808 kilometers

Step-by-step explanation:

Given: On Saturday Keisha ran 3.218 \text{kilometer}. on Sunday she ran  2.41 \text{kilometer}.

To Find: How much further did she run on Saturday than on Sunday.

Solution:

Kilometers run by keisha on saturday =3.218 \text{kilometer}

Kilometers run by keisha on sunday   =2.41 \text{kilometer}

Now,

kilometers covered further by keisha on saturday than sunday

                    =\text{kilometers covered on Saturday}-\text{kilometers covered on Sunday}

putting values,

                    3.218-2.41

                    0.808 \text{kilometer}

keisha run 0.808 \text{kilometer} further on saturday than on sunday.

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sladkih [1.3K]

Answer:

67

Step-by-step explanation:

6 0
3 years ago
1) What is the solution to x - 5 = 27?
Phoenix [80]
X - 5 = 27

Isolate the x, add 5 to both sides (because of equal sign)

x - 5 = 27
x - 5 (+5) = 27 (+5)
x = 27 + 5
x = 32

x = 32 is your answer

hope this helps
3 0
3 years ago
A part selected for testing is equally likely to have been produced on any one of six cutting tools.
JulijaS [17]

Answer:

a)S= (1,2,3,4,5,6)

b) 1/6 or 16.67%

c) 1/3 or 33.33%

d) 5/6 or 83.33%

Step-by-step explanation:

a) Sample space is the list of all the possible sample in this its either tool 1,2,3,4,5 or 6

b) probability of selecting from tool 1 is equally likely to picking from any cutting tool therefore it

1/6 or 16.7%

c) probability of selecting from any tool is 16.7% so probability of selecting from 3 or 5 = 16.67% + 16.67% = 33.3%

d) if the part is not from tool 4 then its from tool 1, or tool 2 or tool 3 or tool 5 or tool 6 therefore its

1/6+1/6+1/6+1/6+1/6 = 5/6 or 8.33%

8 0
3 years ago
The number of pizzas ordered on friday evenings between 5:30 and 6:30 at a pizza delivery location for the last 10 weeks is show
Ainat [17]
For a smoothing constant of 0.2

Time period – 1 2 3 4 5 6 7 8 9 10

Actual value – 46 55 39 42 63 54 55 61 52

Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90

Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12

The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8

Time period – 1 2 3 4 5 6 7 8 9 10

Actual value – 46 55 39 42 63 54 55 61 52

Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80

Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17

The mean forecast for period 11 is 53.56


Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
7 0
3 years ago
Maureen went on a 3 day 50 mile trip. the first day she biked 17 7/8 miles . the second day she biked 18 5/7 miles. How many mil
Inessa [10]
To find the miles for 3rd day, we take away the miles she biked for the first two day from the total.

   50 - 17 \dfrac{7}{8} - 18\dfrac{5}{7}

=50 - 17 \dfrac{7 \times 7}{8 \times 7} - 18\dfrac{5 \times 8}{7 \times 8}

= 48 \dfrac{112}{56}  - 17 \dfrac{49}{56} - 18\dfrac{40}{56}

= 13 \dfrac{23}{56}   \text { miles }

-----------------------------------------------------------------------------------
Answer: She traveled 13 23/56 miles on the third day.
-----------------------------------------------------------------------------------
7 0
3 years ago
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