We want to find
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
A is your answer 3.4
Use Pythagorean Theroum
10.2 squared = 9.6 squared + x squared
104= 92.6+x squared
x squared = 11.4
x= 3.37
round x to 3.4
Hope that helps!
Q -------------R------------S
suppose this is your line,
R is the mid point
and it's given that
QR = 2x
and
RS = x+3
as R is the mid point of QS
so,
QR = RS
then,
2x = x + 3
2x - x =3
x = 3
as,
it's given that RS = x + 3
then,
RS = 3 + 3
= 6 units.
Answer:
x = 5/2 thì y = 35 và x = -5 thì y = 5
Step-by-step explanation:
thay y = 4x + 25 vào phương trình y = 2x ^ 2 + 9x ta có:
4x + 25 = 2x ^ 2 + 9x
⇒2x ^ 2 + 5x - 25 = 0
⇒ x = 5/2 và x = -5
thay x = 5/2 vào phương trình y = 4x + 25 ⇒ y = 4*(5/2) + 25 = 35
thay x = -5 vào phương trình y = 4x + 25 ⇒ y = 4*(-5) + 25 = 5
Answer:
K = (1/2)r^2(sin(θ) +θ)
Step-by-step explanation:
The area of the triangle to the left is ...
A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)
The area of the sector to the right is ...
A2 = (1/2)r^2θ
so the total area of the blue shaded region is ...
K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ
K = (1/2)r^2(sin(θ) +θ)
