Answer:
$90,119.405
Explanation:
Given:
Periodic payment (p) = $25,000
Number of payment (n) = 5
Interest rate (r) = 12% = 12 / 100 = 0.12
Present value = ?
Computation of Present value :
![Present\ Value = PMT [\frac{1-(1+i)^{-n}}{i}] \\\\ Present\ Value= 25,000 [\frac{1-(1+0.12)^{-5}}{0.12}]\\\\Present\ Value= 25,000 [\frac{1-(1.12)^{-5}}{0.12}]\\\\Present\ Value= 25,000 [\frac{1-0.567426856}{0.12}]\\\\Present\ Value= 25,000 [\frac{0.432573144}{0.12}]\\\\Present\ Value= 25,000 [3.6047762]\\\\Present\ Value= 90,119.405](https://tex.z-dn.net/?f=Present%5C%20Value%20%3D%20PMT%20%5B%5Cfrac%7B1-%281%2Bi%29%5E%7B-n%7D%7D%7Bi%7D%5D%20%5C%5C%5C%5C%20Present%5C%20Value%3D%2025%2C000%20%5B%5Cfrac%7B1-%281%2B0.12%29%5E%7B-5%7D%7D%7B0.12%7D%5D%5C%5C%5C%5CPresent%5C%20Value%3D%2025%2C000%20%5B%5Cfrac%7B1-%281.12%29%5E%7B-5%7D%7D%7B0.12%7D%5D%5C%5C%5C%5CPresent%5C%20Value%3D%2025%2C000%20%5B%5Cfrac%7B1-0.567426856%7D%7B0.12%7D%5D%5C%5C%5C%5CPresent%5C%20Value%3D%2025%2C000%20%5B%5Cfrac%7B0.432573144%7D%7B0.12%7D%5D%5C%5C%5C%5CPresent%5C%20Value%3D%2025%2C000%20%5B3.6047762%5D%5C%5C%5C%5CPresent%5C%20Value%3D%2090%2C119.405)
We be will invest $90,119.405 (approx).
Answer:
A). A real estate development company wants to estimate the probable sales of construction services on the basis of marriage rates, population movement in the region, and interest rates on construction loans.
Explanation:
Multiple regression is elucidated as the statistical technique employed to determine the association between two or more dependent or response and independent/explanatory variables.
As per the question, the multiple regression can be employed in the first situation where 'a real estate company wishes to forecast the probable sales of construction on the basis of....loans.' Multiple regression analysis would help in representing the linear relationship between these two variables that helps in ensuring effective analysis and making predictions and ensuring optimum output. Thus, <u>option A</u> is the correct answer.
Answer:
The multiple choices are:
$5,589.04
$7,452.05
$4,890.41
$5,876.71
$6,410.96
Amount invested in K is $6,410.96
Explanation:
L+K=12,000
from the return perspective
0.0975=K/12000*0.0805+L/12000*0.117
K=12000-L
Substitute for K in the second equation
0.0975=(12000-L)/12000*0.0805+L/12000*0.117
0.0975=(966-0.0805L)/12000+0.117L/12000
0.0975=(966-0.0805L+0.117L)/12000
12000*0.0975=966+0.0365
L
1170
-966=0.0365L
204=0.0365L
L=204/0.0365
L=$ 5,589.04
K=$12,000-$ 5,589.04
K=$6,410.96
Answer:
$14
Explanation:
Sam parks his car for 8 hours, the first two hours cost $5 and he would pay $0.75 for every half hour after the first two hours . That means he would pay $1.50 for every hour after the first two hours.
He spent 6 hours extra. The total amount that would be paid = $1.50 × 6 = $9
He would pay a total of $9 for the 6 hours extra he parked his car.
The cost of parking for the 8 hours is = $9 + $5 = $14
I hope my answer helps you
Answer:
a. $1508
Explanation:
June 1 150 units
June 10 200 units
June 15 200 units
June 28 150 units
Total 700 units
Out of above, only 210 units are in hand. Under LIFO method, 150 units are from 1st June and 60 units are from 10th June.
Date Units (a) Per unit cost (b) Ending inventory (a*b)
June 1 150 $6.93 (1040/150) $1.040
June 10 60 $7.8 (1560/200) $468
Total 210 $1,508
So, using the LIFO inventory method, the value of the ending inventory on June 30 is $1,508
