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timama [110]
3 years ago
5

Please help not sure how to do these

Mathematics
2 answers:
o-na [289]3 years ago
7 0

We're given two points and two half lines, aka rays.


Point slope form says the line through (a,b) with slope m is


y-b = m(x-a)


We can write that in slope-intercept form:


y = mx + (b-ma)


The left line goes two up for every one to the right, that's a slope of 2. It ends at (-1,-3). So that line is:


y = 2x + (-3 -2(-1)) = 2x-1


We turn that into the ray we like with the condition x \le -1 so it ends at our point.


The right ray has slope 1 and endpoint (1,5). That's x \ge 1 with the line


y=  x + (5-1(1))= x+4


Answer:


y = 2x-1 \textrm{  if  } x \le -1


y =x+4 \textrm{  if  } x \ge 1


Oksanka [162]3 years ago
4 0

For the bottom graph slope = 2 and when x = -1 f(x) = -3 so equation is

f(x )= 2x - 1.



{ 2x - 1 ( x <= -1)

f(x) = {

{ x ( x >= 1)

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Values equivalent to 1/4​
mylen [45]

Answer:

0.25, 4/16, theres like a million more

Step-by-step explanation:

is that what youre looking for?

6 0
3 years ago
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Why is the slope of this graph?
Tom [10]

Answer:

1/2.

Step-by-step explanation:

There seem to be a couple prominent points on the line. We can use two of them to find the slope.

(0, 75)

(30, 90)

(90 - 75) / (30 - 0) = 15 / 30 = 3 / 6 = 1/2.

Hope this helps!

7 0
3 years ago
The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviat
nexus9112 [7]

Answer:

Two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

Step-by-step explanation:

We are given that the diameters of bolts produced in a machine shop are normally distributed with a mean of 5.65 millimeters and a standard deviation of 0.07 millimeters.

<em>Let X = diameters of bolts produced in a machine shop</em>

So, X ~ N(\mu=5.65,\sigma^{2} = 0.07^{2})

The z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean

            \sigma = standard deviation

<u>Now, we have to find the two diameters that separate the top 4% and the bottom 4%.</u>

  • Firstly, Probability that the diameter separate the top 4% is given by;

        P(X > x) = 0.04

        P( \frac{X-\mu}{\sigma} > \frac{x-5.65}{0.07} ) = 0.04

        P(Z > \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the top 4% is given as 1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = 1.7507

              x-5.65 = 0.07 \times 1.7507

                         x = 5.65 + 0.122549 = 5.77

  • Secondly, Probability that the diameter separate the bottom 4% is given by;

        P(X < x) = 0.04

        P( \frac{X-\mu}{\sigma} < \frac{x-5.65}{0.07} ) = 0.04

        P(Z < \frac{x-5.65}{0.07} ) = 0.04

<em>So, the critical value of x in z table which separate the bottom 4% is given as -1.7507, which means;</em>

                 \frac{x-5.65}{0.07}  = -1.7507

              x-5.65 = 0.07 \times (-1.7507)

                         x = 5.65 - 0.122549 = 5.53

Therefore, the two diameters that separate the top 4% and the bottom 4% are 5.77 and 5.53 respectively.

4 0
3 years ago
QUESTION 4
zlopas [31]

Answer:

17,912,62 it that answer

5 0
2 years ago
Pleaseeeeeeeee helpppppp
Hoochie [10]
Using the property of inverse, f^{-1}(f(x))=x, we can extend the given table
x  f(x)  f^(-1)(f(x)) 
-1    1    -1
2     3     2                  f^(-1)(3)=f^{-1}(f(2))=2
3     6     3
5     7     5
7     8     7                  f^(-1)(8)=f^{-1}(f(7))=7

5 0
3 years ago
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