Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
x^2-x+5
Step-by-step explanation:
(f-g)(x)=f(x)-g(x)
= (x^2 + 3) - (x - 2) (Don’t forget the -1 multiplies to the x AND -2
= x^2 + 3 - x + 2
=x^2-x+5
Whatever% of anything is just (whatever/100) * anything.
therefore, if an item has been discounted by 40%, the discounte is that 40%, what is 40% of the price "p"? (40/100) * p or 0.4p.
Answer:
any of the below:
Step-by-step explanation:
12/30
6/15
2/5
Answer:
-12
Step-by-step explanation:
Just sustitute the z for -4
z+z+z
-4+(-4)+(-4)
=-12
I hope this help :)
