Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Answer is C. 13 Find with Magnitude √(x1-x2)²+(y1-y2)² = √25+ 144 = √169 = 13 units
Answer:
at least 51,569 blocks ( same as 51569)
Step-by-step explanation:
973 * 53
Answer: See each part below.
1) A, B, and C are the coefficients in order when it equals 0. Move over the 4 and you have 5, 9, -4 or Choice B.
3) If you graph the equation, it will be above the x-axis. Therefore, it has no roots. Choice D
4) Choice A is correct. Use the coefficients: A = 4, B = 3, C = -10. Simply plug those into the quadratic equation and you will get -2 and 1.25.