Area of a rectangle is 100 sq ft. The length is 10 ft longer than twice it’s width. What is the length and the width.
1 answer:
The length of the rectange is 20ft and width of the 5ft.
<u>Step-by-step explanation:</u>
Let us consider a rectangle and its area is known to be 100 sq ft.
We are given the information that the length of the rectangle is 10ft longer than twice its width.
⇒Length l = 2w+10.
Where w is the width of the rectangle.
The formula for area of the rectangle A = length × width.
A= (2w+10)×w.
100 = .
0=.
Thus it forms an quadratic equation we have to solve for the solution.
0=(2w-10)(w+10).
2w-10=0. w+10=0.
2w=10. w=-10. (negative value cannot be choosed.)
w=.
w=5ft.
Thus width is is 5 ft.
Length = 2(5)+10.
=10+10.
=20ft.
Thus the length is 20ft.
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Given:
θ = 60°
Radius = 8 in
To find:
The area of the shaded segment.
Solution:
Vertically opposite angles are congruent.
Angle for the shaded segment = 60°
<u>Area of the sector:</u>
A = 33.5 in²
Area of the sector = 33.5 in²
<u>Area of triangle:</u>
A = 32 in²
Area of the triangle = 32 in²
Area of segment = Area of sector - Area of triangle
= 33.5 in² - 32 in²
= 1.5 in²
The area of the shaded segment is 1.5 square inches.