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3 years ago

Which statements are true about the solution 2 < x - 7 and its graph? Check all that apply.

Mathematics

2 answers:

Mashutka [201]3 years ago

8 0

Answer:

O x >9

The arrow points left

Step-by-step explanation:

Explanation:-

Given 2 < x-7

adding '7' on both sides, we get

⇒ 2 + 7 < x -7 +7

⇒ 9 < x

⇒ x>9

Given inequality 2 < x -7

The arrow points left

Final answer:-

solution is x >9

The arrow points left

kherson [118]3 years ago

6 0

Answer:

B,D,F

Step-by-step explanation:

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Katen [24]

Answer:

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Step-by-step explanation:

becuse she is mor likely to draw a vowel

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3 years ago

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∠E∠E and ∠F∠F are vertical angles with m∠E=9x+12m∠E=9x+12 and m∠F=3x+24m∠F=3x+24 .

Mama L [17]

Since ∠E and ∠F are vertical angles, they are congruent, meaning that m∠E = m∠F

Plugging in the equations that were originally given, we can form the equation 9x + 12 = 3x + 24

Subtract both sides of the equation by 3x

6x + 12 = 24

Subtract 12 from both sides

6x = 12

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This should be your answer. Have an awesome day! :)

3 0

3 years ago

A square swimming pool with the perimeter of 156 feet find the length of one side

frosja888 [35]

156 divided by 4 is 39 So each side is 39

3 0

4 years ago

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What number increased by 75% is 35

Ne4ueva [31]

To solve this, you would do:

x + 75% * x = 35

7/4 * x = 35

x = 20

8 0

3 years ago

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The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago