Answer:
B. 3x+5−4x=−(x+8)
Explanation:
3x+5−4x=−(x+8)
Step 1: Simplify both sides of the equation.
3x+5−4x=−(x+8)
3x+5+−4x=−x+−8
(3x+−4x)+(5)=−x−8
−x+5=−x−8
−x+5=−x−8
Step 2: Add x to both sides.
−x+5+x=−x−8+x
5=−8
Step 3: Subtract 5 from both sides.
5−5=−8−5
0=−13
So, there is no solution
Hope this Helps!
The answer is 30.
8 x 5 =40
40 - 10 = 30
Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
