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4 years ago

Find the surface area of a square based pyramid if the edge of the base is 8 inches and the slant height is 20 inches.

Mathematics

1 answer:

Sliva [168]4 years ago

7 0

Answer:

384 Square Inches

Step-by-step explanation:

Given a square pyramid with base side edge and slant height

$\text{Surface Area} = A+\dfrac12 ps, where:\\A=$Area of Base\\p=Perimeter of base\\s=Slant Height$

In the given pyramid:

Slant Height=20 inches
Base Edge = 8 Inches

Therefore:

Area of Base, A =8 X 8 =64 Square Inches

Perimeter of base, p =4 X 8 =32 Inches

$\text{Surface Area} = 64+\dfrac12 *32*20\\=64+320\\=384$ Square Inches$

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4 years ago

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3 years ago

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George had 1 sheet of paper.He cuts it into 6 inches by 5 inches,and 3 inches by 6 inches.What were the dimension and total area

7nadin3 [17]

Answer:

A. 8 inches by 6 inches.

B. $48\text{ inches}^{2}$ .

Step-by-step explanation:

We have been given that George had 1 sheet of paper. He cuts it into 6 inches by 5 inches and 3 inches by 6 inches.

We can see that two dimensions of small parts of paper sheet have one dimension same (6 inches), therefore, one dimension of original sheet of paper will be 6 inches.

We can figure out second dimension of original paper sheet by adding the lengths of dimension other than 6. So the second dimension will be 8 inches (5+3).

Therefore, the dimensions of our original sheet will be 8 inches by 6 inches.

Now let us figure out the total area of the original sheet of paper by multiplying 8 by 6.

$\text{The total area of the original sheet of paper}=8\text{ inches}\times 6\text{ inches}$

$\text{The total area of the original sheet of paper}=48\text{ inches}^{2}$

Therefore. the area of original sheet of paper will be $48\text{ inches}^{2}$ .

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3 years ago

A sphere is inscribed in a cylinder. Use complete sentences and geometric formulas to compare the surface area of the sphere and

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The word inscribed means that the sphere is inside the cylinder and its diameter is equal to the height and diameter of the cylinder. The surface area of the sphere is equal to
SA (sphere) = πd²
where d is the diameter.
That of the cylinder is,
SA (cylinder) = πd(h + d/2)
Since h is also equal to d
SA (cylinder) = πd(d + d/2) = 3πd²/2
Therefore, the surface area of the cylinder is approximately 1.5 times that of the sphere.

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3 years ago

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