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kompoz [17]
2 years ago
13

Is my answer correct?

Mathematics
2 answers:
oee [108]2 years ago
7 0
<h2>Question:- Find X</h2><h3>Given:- </h3>
  1. A rectangle consist of 4 identical triangle
  2. diagonals of rectangle are at 90° to each other
  3. length of half of the one diagonal is 8 in
  4. length of the half of the other diagonal is X in
  5. Area of the rectangle = 48 in²
  6. Base of triangle = 8in
  7. height of the triangle = x in

<h2>Answer :- X = 3 in </h2>

<h3>Formula :- Area of the rectangle is equal to the sum of the area of the all four the triangle </h3>

area \: of \: rectangle \\= 4 \times area \: of \:identical \:  triangle

<h2>Explanation :- </h2>

area \: of \: rectangle =\\ 4 \times area \: of \:identical \:  triangle

48 {in}^{2}  = 4 \times  \frac{1}{2}  \times base \times height \\ 48 {in}^{2}  = 2 \times base  \times height \\  \frac{48}{2}  = 8 \times height \\  \frac{ \cancel{48} {}^{ \:  \: 24} }{ \cancel{2}}  = 8 \times height \\  \frac{24}{8}  = height \\  \frac{ \cancel{24} {}^{ \:  \: 3} }{ \cancel{8}}  = height \:  \\ height = x = 3in \:

tensa zangetsu [6.8K]2 years ago
3 0

Answer:

  • No, x = 3 in

Step-by-step explanation:

The area of the rhombus is half the product of its diagonals

  • A = 1/2(2x*16) = 48
  • 16x = 48
  • x = 48/16
  • x = 3

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Question:- Find

\left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3}

Answer:-

\left(\frac{5}{12}\right)^{4}\left(\frac{12}{15}\right)^{3}

Taking power inside the bracket

\frac{5^{4} }{ {12}^{4} }  \times  \frac{ {12}^{3} }{ {15}^{3} }

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Power\:Form-> \frac{ 5 }{12 \times {3}^{3} }

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3 years ago
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<h3>Weights</h3>

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