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Readme [11.4K]
3 years ago
5

two toy rockets are launched straight up into the air. the height, in feet, of each rocket at t seconds after launch is given by

the polynomial equations shown. write an equation to find the difference in height of rocket a and rocket b. predict the difference in height after 5 seconds rocket a: d1=-16t2+122t rocket bd2=-16t2+84t
Mathematics
1 answer:
prohojiy [21]3 years ago
6 0

d₁ = -16t² + 122t

d₂ = -16t² + 84t

d = d₁ - d₂

d =  -16t² + 122t  -  (-16t² + 84t)

d = 38t

After five seconds, t=5,

d = 38(5) = 190

Answer: 190 feet

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A water delivery truck is filling the water tank at Morgan's house. The truck arrived with 2400 L of water. The number of liters
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Answer:

11.81 minutes

Step-by-step explanation:

Here is a simple step-by-step explaination of how to solve this word problem:

Since the truck has 2,400L in it to begin with, the first part of our equation will be 2,400L

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Next we know that the water in the truck decreases at a <u>rate</u> of 110L/min, or <u>Liters per minute</u>.

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L = -110L + 2400L

Now that we have our equation set up, its time to solve.

To figure out how much water it needs to lose in <u>total</u> to end up with 1100 L left, we subtract 1,100 from 2,400.

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1,300/110=11.81

So the total amount of time it took for the truck to have 1,100 L left is 11.81 minutes. Your answer would be

B. L=-110t + 2400, t=11.8 min

Hope this helps! : )

3 0
2 years ago
Read 2 more answers
Please help
katrin2010 [14]
\dfrac{n^2+3n+2}{n^2+6n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n^2+2n+n+2}{n^2+4n+2n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n(n+2)+1(n+2)}{n(n+4)+2(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{(n+2)(n+1)}{(n+2)(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{n+1}{n+4}-\dfrac{2n}{n+4}=\dfrac{n+1-2n}{n+4}=\dfrac{1-n}{n+4}

Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}
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