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3 years ago

How would i graph y=2/3x+1

Mathematics

2 answers:

belka [17]3 years ago

7 0

Lets look at the actual equation. Y= 2/3x+1

1 is the y intercept in this equation, so we will plot that point first on the graph.

Now we know the slope as well. We know that the slope is 2/3. From the Y intercept, This means we will go up 2 and over 3 for our next point.

Ksju [112]3 years ago

3 0

This will be a straight line
the 2/3 is the slope of the graph and the + 1 is the intersection on the y axis
so the line will pass through y = +1 and the slope (rise / run) will be 2/3

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3 years ago

What is the greatest common factor of 3a^2+30a

Lisa [10]

Answer:

Step-by-step explanation:

3 is a prime number so other than 3x1 3 does not have any other factors

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3 years ago

Help ASAP Please check to see if I have the last part correct. Thanks

7nadin3 [17]

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3 years ago

Read 2 more answers

100 POINTS TO RIGHT AWNSER!!!!

makvit [3.9K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3000586

——————————

The answer is option D) r < 5 or r > – 1.

I'm going to graph each inequality below on a number line.

A) r > 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

The result is found just by joining those two intervals together. Actually that compound inequality only implies

r > – 1

which does not represent all real numbers.

—————

B) r > 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r5~~or~~r$

Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.

—————

C) r < 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r$

Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.

—————

D) r < 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r-1}&\qquad\mathsf{\overset{~~~**************************~~~}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

Now all real numbers are included in the union. So this is the right choice.

Answer: option D) r < 5 or r > – 1.

I hope this helps. =)

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2 years ago

This is a standard deviation contest. You must choose four numbers from the whole numbers 0 to 10 , with repeats allowed. (a) Ch

irina [24]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following instructions :

Choose 4 numbers from the whole numbers 0 - 10

Note : Repetition is allowed

Choose 4 numbers with the smallest possible standard deviation.

The smallest possible value of standard deviation obtainable is 0;

Hence in other to obtain a standard deviation value of 0, then;

The mean squared deviation value must be zero (0)

Σ(X - mean)^2 = 0

To achieve this, the values of X and the mean must be the same.

Hence all 4 numbers (X) must be the same in other to have a mean value which is equal to X

For instance :

If X = 3, 3, 3, 3 (since Repetition is allowed)

Man value = (3+ 3+ 3+ 3) / 4 = 12 / 4 = 3

Σ(3 - 3)² = 0 for all values of x

√Σ(x - mean)² / n = 0 ; if all values of x are the Same

n = Number of observations

A possible list of values is (3,3,3,3)

4 0

2 years ago