11

Mathematics

1 answer:

Cloud [144]3 years ago

8 0

Answer:

force

Step-by-step explanation:

it's literally asking you for the force needed to push the crate lol.

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Linear System Word Problem - Animals

Margaret [11]

Answer:

There were 15 birds at the shelter on Monday

Step-by-step explanation: 15 birds x 5$ =75$ and 8 cats x 6$=48$ 75$ + 48$=123$

4 0

3 years ago

Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root min

Cloud [144]

$7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$ simplified as $11\sqrt{3}- 7\sqrt{6}$ or $1.909$ .

<u>Step-by-step explanation:</u>

We need to Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root minus square root of fifty four. Which is equivalent to $7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$ :

$7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$

⇒ $7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{44}$

⇒ $7\sqrt{3}- 4\sqrt{6} + \sqrt{16(3)} - \sqrt{9(6)}$

⇒ $7\sqrt{3}- 4\sqrt{6} + 4\sqrt{(3)} - 3\sqrt{(6)}$

⇒ $11\sqrt{3}- 4\sqrt{6}- 3\sqrt{(6)}$

⇒ $11\sqrt{3}- 7\sqrt{6}$

$\sqrt{3} = 1.732 , \sqrt{6} = 2.449$

⇒ $11(1.723)- 7(2.449)$

⇒ $1.909$

Therefore, $7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}$ simplified as $11\sqrt{3}- 7\sqrt{6}$ or $1.909$ .

6 0

3 years ago

Please help with this problem.

larisa86 [58]

Answer:

60°, 120°

Step-by-step explanation:

$\frac{ {tan}^{2}x }{2} - 2 {cos}^{2}x = 1 \\ \\ \frac{ {tan}^{2}x - 4{cos}^{2}x }{2} = 1 \\ \\ {tan}^{2}x - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x}{{cos}^{2}x} - 4{cos}^{2}x = 2 \\ \\ \frac{{sin}^{2}x - 4{cos}^{4}x}{{cos}^{2}x} = 2 \\ \\ {sin}^{2}x - 4{cos}^{4}x = 2{cos}^{2}x \\ \\ 4{cos}^{4}x + 2{cos}^{2}x - {sin}^{2}x = 0 \\ \\ 4{cos}^{4}x + 2{cos}^{2}x + {cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 3{cos}^{2}x - 1= 0 \\ \\ 4{cos}^{4}x + 4{cos}^{2}x - {cos}^{2}x - 1= 0 \\ \\4{cos}^{2}x({cos}^{2}x + 1) - 1({cos}^{2}x + 1) = 0 \\ \\ ({cos}^{2}x + 1)(4{cos}^{2}x - 1) = 0 \\ \\ ({cos}^{2}x + 1) = 0 \: or \: (4{cos}^{2}x - 1) = 0 \\ \\ {cos}^{2}x = - 1 \: or \: 4{cos}^{2}x = 1 \\ \\ {cos}x = \sqrt{ - 1} \: which \: is \: not \: possible \\ \therefore \: {cos}^{2}x = \frac{1}{4} \\ \\ \therefore \: {cos}x = \pm\frac{1}{2} \\ \\ \therefore \: {cos}x = \frac{1}{2} \: or \: {cos}x = - \frac{1}{2} \\ \\ \therefore \: {cos}x = {cos}60 \degree \: or \: {cos}x = {cos}120 \degree \\ \\ \therefore \:x = 60 \degree \: \: or \: \: x = 120 \degree$